这样有意义吗?
function revStr($str)
{
$str2 = implode(" ", array_map("strrev", explode(" ", $str)));
$len = strlen($str);
while ($len > 0) {
$str2{$len - 1} = ord($str{$len - 1}) < 97 ? strtoupper($str2{$len - 1}) : strtolower($str2{$len - 1});
$len--;
}
return $str2;
}
$str = 'This is an Apple on eBay';
echo revStr($str);// Siht si na Elppa no yAbe
先用$arr=explode('',$input)分割这个字符串,
然后将数组翻过来array_reverse()
然后遍历$arr
用$a=substr($arr[0],0,1)截取
if(preg_match('/^[a-z]+$/', $a)){
echo '小写字母';
$a=strtoupper($a)
}elseif(preg_match('/^[A-Z]+$/', $a)){
echo '大写字母';
$a = strtolower($a)
}
然后拼起来就完成了
我也来一个,比@util的稍微快点:)
function revStr(&$str) {
$offset = 0;
$isEnd = false;
while(!$isEnd){
$spacePos = strpos($str, ' ', $offset);
if($spacePos === false){
$spacePos = strlen($str);
$isEnd = true;
}
$wordLen = $spacePos - $offset;
$wordLenHalf = $wordLen >> 1;
for ($j = 0; $j < $wordLenHalf; $j++) {
$diff = 0;
$charPos = $offset + $j;
$charPosRev = $spacePos - $j - 1;
$charASCII = ord($str[$charPos]);
$charASCIIRev = ord($str[$charPosRev]);
$diff += ($charASCII <= 90) ? -16 : 16;
$diff += ($charASCIIRev <= 90) ? 16 : -16;
if($diff){
$str[$charPos] = chr($charASCIIRev + $diff);
$str[$charPosRev] = chr($charASCII - $diff);
}else{
$tmp = $str[$charPos];
$str[$charPos] = $str[$charPosRev];
$str[$charPosRev] = $tmp;
}
}
$offset += $wordLen+1;
}
}
$str = 'This is an Apple on eBay';
revStr($str);
echo $str;// Siht si na Elppa no yAbe
神需求,什么乱七八糟的一堆,