都用ajax了，自己拼装data发过去啰，还拘泥于一个form干嘛？

用JQuery和Ajax了那就用这样的代码吧
`
$('#btn-confirm-login').on('click', function(){

$.ajax({
    beforeSend:function(){
            if($('#input-account').val().length == 0) {
                 ui.error("请输入帐号");
                $('#input-account').focus();
                return false;
            }
            if($('#input-password').val().length == 0) {
                 ui.error("请输入密码");
                $('#pinput-password').focus();
                return false;
            }
            return true;
        },
    dataType:"json",
    data:{"user":user,"pwsd":pwsd},
     success: function(i){
            $('#error-msg-tip').html('<p>'+i.info+'</p>').show();
            if(i.status == 1){
                if(i.data == 0){
                    window.location.href = U('public/Index/index');  
                }else{
                    window.location.href = i.data;            
                }
            }else if(i.status == 2){
                var membs = i.data;

// console.log(membs);

                var $con = $('#select-sub-acc');
                $con.empty();
                $.each(membs, function(i, e){
                    var $btn = $("<button></button>");
                    $btn.text(e.uname).data("acc", e.worket).data('uid', e.uid);
                    $btn.on('click', function(){
                        //var worket = $(this).data('acc');
                        var uid = $(this).data('uid');
                        $('#hidden-uid').val(uid);
                        //$('#input-account').val(worket);
                        $('#btn-confirm-login').trigger('click');
                    });
                    $con.append($btn);
                });

                var $dialog = $('#select-sub-acc').dialog({
                    autoOpen: false,
                    height: 200,
                    width: 300,
                    modal: true,
                    title:"请确定一个帐号"
                });
                $dialog.dialog('open');
            }
        }  
});

`